The 2015 NL Wild Card Game: A Singular Baseball Event
The introduction of the second wild-card playoff team in each league in 2012 ignited the latest in a never-ending round of debates between baseball purists and modernists. Purists argued that the expansion of the playoff field cheapened the regular season, bringing it closer in line with the other major sports in terms of percentage of teams qualifying for the postseason. Major League Baseball, on the other hand, argued that it would keep a larger number of clubs in the pennant race, hopefully jacking up attendance and TV ratings in the process. From a competitive standpoint, the change really didn’t seem to be that big of a deal. It basically pitted teams ranked somewhere between fifth and 12th in MLB’s overall pecking order in a one-game showdown, with the side benefit of no longer subjecting a division winner to a “one game and out” end after a successful regular season.
It’s a little bit different scenario this time around in the National League. If today’s standings hold up over the next three weeks, we will be treated to a baseball rarity, as the clubs with the second- and fifth-best records in all of baseball, the Pirates and Cubs, divisional rivals, face a one-game showdown for their postseason lives. For my money, this ranks right up there with any non Super Bowl one-off sporting event on the calendar; it’s a Game 7, Djokovic-Federer, and Spieth-McElroy all rolled into one. When you get down to it, it’s a matchup that would be historically rare even if the two-wild-card system had been in place since the dawn of the divisional era.